Помогите алгебра пж

Ответ:

(x,y)=( $\frac{7}{5}$ - $\frac{16}{5}$ )

Объяснение:

$\left \{ {{3х+y=1} \atop {2x-y=6}} \right.$

$\left \{ {{y=1-3x} \atop {2x-y=6}} \right.$

2x-(1-3x)=6

x= $\frac{7}{5}$

y=1-3× $\frac{7}{5}$

(x,y)=( $\frac{7}{5}$ - $\frac{16}{5}$ )

$\left \{3*\frac{7}{5}-\frac{16}{5}=1 } } \atop {2*\frac{7}{5}-(-\frac{16}{5})=6 }} \right.$

$\left \{ {{1=1} \atop {6=6}} \right.$

(x,y)=( $\frac{7}{5}$ - $\frac{16}{5}$ )

Помогите алгебра пж​