Ответ:
Пошаговое объяснение:
0} \atop {2x^{2} - 7x +5 \leq 0 }} \right." alt="\left \{ {{x(3x-1)>0} \atop {2x^{2} - 7x +5 \leq 0 }} \right." align="absmiddle" class="latex-formula"> 
0 } \atop {(x-1)(x-2,5)\leq 0 }} \right." alt="\left \{ {{x(3x-1)>0 } \atop {(x-1)(x-2,5)\leq 0 }} \right." align="absmiddle" class="latex-formula">
