1) 2arcsin(1/2) = 2·π/6 = π/3; 4arccos(1/2) = 4·π/3 = 4π/3;
π/3 < 4π/3 → 2arcsin(1/2) < 4arccos(1/2).
2) 4arctg1 = 4π/4 = π; 5arccos(-1) = 5π;
π < 5π → 4arctg1 < 5arccos(-1).
3) 1·arcsin1 = π/2; 5arctg1 = 5π/4;
π/2 > 5π/4 → 1·arcsin1 > 5arctg1.
4) 5arccos0 = 5·1 = 5; 2arctg0 = 2·0 = 0.
5 > 0 → 5arccos0 > 2arctg0.
1) 4arcsin(√3/2) - 4arcsin(-√3/2) = 4·π/3 + 4·π/3 = 8π/3
2) 4arccos(√2/2) - 4arccos(-√2/2) = 4·π/4 - 4·(π - π/4) = π - 4·3π/4 = π - 3π = -2π.
3) 5arctg√3 - 5arctg(-√3) = 5·π/3 + 5·π/3 = 10π/3
4) 2arctg(√3/3) - 2arctg(√3/3) = 0