Решите уравнение (x+4)(x-2)=x(2-3x)
(x + 4) (x - 2) = x(2 - 3x) \\ x {}^{2} - 2x + 4x - 8 = 2x - 3x {}^{2} \\ 4x {}^{2} - 2x - 2x + 4x - 8 = 0 \\ 4x {}^{2} - 8 = 0 \\ x {}^{2} = 8 \div 4 \\ x {}^{2} = 2 \\ x = - + \sqrt{2}