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Решите задачу:

$(\frac{3}{4} + \frac{1}{2} + \frac{5}{12}) \times 12 = \frac{(3 \times 3 + 1\times 6 + 5) \times 12}{12} = 9 + 6 + 5 = 20$

$24 \times ( \frac{1}{2} + \frac{3}{8} + \frac{5}{6} ) = \frac{24 \times (12 + 3 \times 3 + 5 \times 4)}{24 } = 12 + 9 + 20 = 41$

$4 \times \frac{1}{3} + 4 \times \frac{2}{5} + 4 \times \frac{2}{15} = 4 \times ( \frac{1}{3} + \frac{2}{5} + \frac{2}{15} ) = 4 \times \frac{5 + 2 \times 3 + 2}{15} = 4 \times \frac{5 + 6 + 2}{15} = \frac{4 \times 13}{15} \frac{52}{15} = 3 \frac{7}{15}$

$7 \times \frac{2}{3} + 7 \times \frac{1}{2} + 7 \times \frac{5}{6} = 7 \times ( \frac{2}{3} + \frac{1}{2} + \frac{5}{6}) = 7 \times \frac{2 \times 2 + 3 + 5}{6} = 7 \times \frac{12}{6} = 7 \times 2 = 14$