Решите уравнение x^2+5x/3 -x+3/2=2x-2/8

Решите задачу:

$\frac{ {x}^{2} + 5x }{3} - \frac{x + 3}{2} = \frac{2x - 2}{8} \\ \frac{ {x}^{2} + 5x }{3} - \frac{x + 3}{2} = \frac{2 + \times (x - 1)}{8} \\ \frac{ {x}^{2} + 5x }{3} - \frac{x + 3}{2} = \frac{x - 1}{4} \\ \frac{4 \times ( {x}^{2} + 5x}{3} - 2 \times (x + 3) = (x - 1) \\ 4x {}^{2} + 20x - 6x - 18 = 3x - 3 \\ 4 {x}^{2} + 14x - 18 = 3x - 3 \\ 4 {x}^{2} + 14x - 18 - 3x + 3 = 0 \\ 4 {x}^{2} + 11x - 15 = 0 \\ 4 {x}^{2} + 15x - 4x - 15 = 0 \\ x \times (4x + 15) - (4x + 15) = 0 \\ (4x + 15) \times (x - 1) = 0$

$4x + 15 = 0 \\ 4x = - 15 \\ x = - \frac{15}{4} = - 3.75$

$x - 1 = 0 \\ x = 1$