Решите уравнения 3) 7/8 * (-4/9)=2/7x 4) 3/5x + (9x/3)=10

$1)\frac{7}{8} \times ( - \frac{4}{9} ) = \frac{2}{7} x \\ \\ \frac{7}{2} \times ( - \frac{1}{9} ) = \frac{2}{7} x \\ \\ - \frac{7}{18} = \frac{2}{7} x \\ \\ x = - \frac{7}{18} \div \frac{2}{7} \\ \\ x = - \frac{7}{18} \times \frac{7}{2} \\ \\ x = - \frac{49}{36} = - 1 \frac{13}{36} \\ \\ \\ \\ 2) \frac{3}{5} x + ( \frac{9x}{3} ) = 10 \\ \\ 9x + 45x = 150 \\ \\ 54x = 150 \\ \\ x = 150 \div 54 \\ \\ x = \frac{25}{9} = 2 \frac{7}{9}$

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