Ответ:
-1 и 1
Объяснение:
(x^2-x^{-10})(x^2+x^{-10})=0<=>\\<=>(x-x^{-5})(x+x^{-5})(x^2+x^{-10})=0<=>(x^6-1)(x^6+1)(x^{12}+1)=0=>\\=>x^6-1=0=>x=1;x=-1\\2)x^4-x^{-20}=0<=>\frac{x^{24-1}}{x^{20}} =0=>x^{24}-1=0=>x=1;x=-1" alt="1)x^4-x^{-20}=0<=>(x^2-x^{-10})(x^2+x^{-10})=0<=>\\<=>(x-x^{-5})(x+x^{-5})(x^2+x^{-10})=0<=>(x^6-1)(x^6+1)(x^{12}+1)=0=>\\=>x^6-1=0=>x=1;x=-1\\2)x^4-x^{-20}=0<=>\frac{x^{24-1}}{x^{20}} =0=>x^{24}-1=0=>x=1;x=-1" align="absmiddle" class="latex-formula">