Упростите выражение.

Ответ:

Объяснение:

$\frac{9}{x-3}-\frac{3x}{(x-3)^2}:\frac{3x}{x^2-9}-\frac{2x-3}{x-3}=\\\\=\frac{9}{x-3}-\frac{3x}{(x-3)^2}*\frac{x^2-9}{3x}-\frac{2x-3}{x-3}=\\\\=\frac{9}{x-3}-\frac{3x*(x^2-9)}{(x-3)^2*3x}-\frac{2x-3}{x-3}=\\\\=\frac{9}{x-3}-\frac{x^2-9}{(x-3)^2}-\frac{2x-3}{x-3}=\\\\=\frac{9}{x-3}-\frac{(x-3)(x+3)}{(x-3)^2}-\frac{2x-3}{x-3}=\\\\=\frac{9}{x-3}-\frac{(x+3)}{(x-3)}-\frac{2x-3}{x-3}=\\\\=\frac{9-(x+3)-(2x-3)}{x-3}=\\\\=\frac{9-x-3-2x+3}{x-3}=\\\\=\frac{9-3x}{x-3}=\frac{3(3-x)}{x-3}=3$