x1*x2=(1-i*3)(1+i*3)/4=(1-9(i)^2)/4=10/4=2,5
x1+x2=1
x^2-x+2,5=0
2) 2x+xi-y+yi=1+3i
2x-y=1
x+y=3
4x=4 x=1 y=3-x=2
3) (√3+i√2)^2/(3+2)=(1+2i√6)/5=1/5+(2√6/5)i
1/4+(√3/2)i-3/4=-1/2+(√3/2)i
в) (1+(-1)^7*i)/(2+(-1)^8*i)=(1-i)/(2+i)=(1-i)(2-i)/5=(2-3i-1)/5=
=(1-3i)/5=1/5-(3/5)i