перепишем условие: ![\displaystyle\left\{{{|a^2-(a+1)^2|+|(a+2)^2-(a+3)^2|=18}\atop{a\in N}}\right. \displaystyle\left\{{{|a^2-(a+1)^2|+|(a+2)^2-(a+3)^2|=18}\atop{a\in N}}\right.](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5C%7B%7B%7B%7Ca%5E2-%28a%2B1%29%5E2%7C%2B%7C%28a%2B2%29%5E2-%28a%2B3%29%5E2%7C%3D18%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.)
раскрыв скобки внутри модулей, приведя подобные слагаемые, вынеся общий множитель и сократив на него обе части уравнения, получили: ![\displaystyle\left\{{{|a+\frac{1}{2}|+|a+\frac{5}{2}|=9}\atop{a\in N}}\right. \displaystyle\left\{{{|a+\frac{1}{2}|+|a+\frac{5}{2}|=9}\atop{a\in N}}\right.](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5C%7B%7B%7B%7Ca%2B%5Cfrac%7B1%7D%7B2%7D%7C%2B%7Ca%2B%5Cfrac%7B5%7D%7B2%7D%7C%3D9%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.)
1) если
, то
![\displaystyle\left\{{{-a-\frac{1}{2}-a-\frac{5}{2}=9}\atop{a\in N}}\right.\displaystyle\left\{{{a=-6}\atop{a\in N}}\right. \displaystyle\left\{{{-a-\frac{1}{2}-a-\frac{5}{2}=9}\atop{a\in N}}\right.\displaystyle\left\{{{a=-6}\atop{a\in N}}\right.](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5C%7B%7B%7B-a-%5Cfrac%7B1%7D%7B2%7D-a-%5Cfrac%7B5%7D%7B2%7D%3D9%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.%5Cdisplaystyle%5Cleft%5C%7B%7B%7Ba%3D-6%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.)
система решений не имеет
2) если
, то
![\displaystyle\left\{{{-a-\frac{1}{2}+a+\frac{5}{2}=9}\atop{a\in N}}\right.\displaystyle\left\{{{0a=7}\atop{a\in N}}\right. \displaystyle\left\{{{-a-\frac{1}{2}+a+\frac{5}{2}=9}\atop{a\in N}}\right.\displaystyle\left\{{{0a=7}\atop{a\in N}}\right.](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5C%7B%7B%7B-a-%5Cfrac%7B1%7D%7B2%7D%2Ba%2B%5Cfrac%7B5%7D%7B2%7D%3D9%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.%5Cdisplaystyle%5Cleft%5C%7B%7B%7B0a%3D7%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.)
система решений не имеет
3) если
, то
![\displaystyle\left\{{{a+\frac{1}{2}+a+\frac{5}{2}=9}\atop{a\in N}}\right.\displaystyle\left\{{{a=3}\atop{a\in N}}\right. \displaystyle\left\{{{a+\frac{1}{2}+a+\frac{5}{2}=9}\atop{a\in N}}\right.\displaystyle\left\{{{a=3}\atop{a\in N}}\right.](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cleft%5C%7B%7B%7Ba%2B%5Cfrac%7B1%7D%7B2%7D%2Ba%2B%5Cfrac%7B5%7D%7B2%7D%3D9%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.%5Cdisplaystyle%5Cleft%5C%7B%7B%7Ba%3D3%7D%5Catop%7Ba%5Cin%20N%7D%7D%5Cright.)
ответ: ![a=3 a=3](https://tex.z-dn.net/?f=a%3D3)
тогда условный ряд чисел: 3, 4, 5, 6, причём
![|3^2-4^2|+|5^2-6^2|=|9-16|+|25-36|=|-7|+|-11|=7+11=18 |3^2-4^2|+|5^2-6^2|=|9-16|+|25-36|=|-7|+|-11|=7+11=18](https://tex.z-dn.net/?f=%7C3%5E2-4%5E2%7C%2B%7C5%5E2-6%5E2%7C%3D%7C9-16%7C%2B%7C25-36%7C%3D%7C-7%7C%2B%7C-11%7C%3D7%2B11%3D18)