Упростите...

Решите задачу:

$(x-5)^2-7=x^2-10x+25-7=x^2-10x+18$

$6y+(y-3)^2=6y+y^2-6y+9=y^2+9$

$(4a-5b)^2-16a(a-3b)=16a^2-40ab+25b^2-16a^2+48ab=8ab+25b^2$

$(4m+3n)^2+(2m-6n)^2=16m^2+24mn+9n^2+4m^2-24mn+36n^2=20m^2+45n^2$

$x(x-2)-(x-3)^2=x^2-2x-x^2+6x-9=4x-9$

$(8p-q)^2-(4p-q)(16p+3q)=64p^2-16pq+q^2-64p^2-12pq+16pq+3q^2=4q^2-12pq$

$y(3y-2)^2-9y(4+y)^2=y(9y^2-12y+4)-9y(16+8y+y^2)=9y^3-12y^2+4y-144y-72y^2-9y^3=-84y^2-140y$

$(x+4)^2-(x-2)(x+2)=x^2+8x+16-x^2+4=8x+20$

$(8a-3b)(8a+3b)-(6a-5b)^2=64a^2-9b^2-36a^2+60ab-25b^2=28a^2+60ab-34b^2$

$(m-3)(m+4)-(m+2)^2+(4-m)(m+4)=m^2+4m-3m-12-m^2-4m-4+16-m^2=-m^2-3m$