Между числами -1/27 и -9 вставьте 4 числа так, чтобы они образовали геометрическую...

$b_{1};b_{2};b_{3};b_{4};b_{5};b_{6}$

$b_{1}=-\frac{1}{27};$

$b_{6}=-9;$

Найти: $b_{2};b_{3};b_{4};b_{5}$

b_{6}=b_{1}q^{5}" alt="b_{n}=b_{1}q^{n-1}=>b_{6}=b_{1}q^{5}" align="absmiddle" class="latex-formula">

$q^{5}=\frac{b_6}{b_1}$

$q^{5}=-9:(-\frac{1}{27})$

$q^{5}=9*27$

$q^{5}=243$

$q^{5}=3^5$

$q=3$

b_{2}=-\frac{1}{27}*3=-\frac{1}{9};" alt="b_{2}=b_{1}q=>b_{2}=-\frac{1}{27}*3=-\frac{1}{9};" align="absmiddle" class="latex-formula">

b_{3}=-\frac{1}{9}*3=-\frac{1}{3};" alt="b_{3}=b_{2}q=>b_{3}=-\frac{1}{9}*3=-\frac{1}{3};" align="absmiddle" class="latex-formula">

b_{4}=-\frac{1}{3}*3=-1;" alt="b_{4}=b_{3}q=>b_{4}=-\frac{1}{3}*3=-1;" align="absmiddle" class="latex-formula">

b_{5}=-1*3=-3" alt="b_{5}=b_{4}q=>b_{5}=-1*3=-3" align="absmiddle" class="latex-formula">

Ответ: $-\frac{1}{9};-\frac{1}{3};-1;-3$