Решите уравнения: 4x^2-x^4=0 5x^4-125x^2=0 3x^4+27x^2=0

$4 {x}^{2} - 4 {x}^{4} = 0 \\ 4x \times (1 - {x}^{2} ) = 0 \\ x \times (1 - {x}^{2} ) = 0 \\ 1){x}^{2} = 0 \\ 2)1 - {x}^{2} = 0$

Отсюда: х¹ = 0, х² = -1, х³ = 1.

$5 {x}^{4} - 125 {x}^{2} = 0 \\ 5 {x}^{2} \times ( {x}^{2} - 25) = 0 \\ {x}^{2} \times ( {x}^{2} - 25) = 0 \\ 1) {x}^{2} = 0 \\ 2) {x}^{2} - 25 = 0$

Отсюда: х¹ = 0, х² = 5, х³ = -5.

$3 {x}^{4} + 27 {x}^{2} = 0 \\ 3 {x}^{2} \times ( {x}^{2} + 9) = 0 \\ {x}^{2} \times ( {x}^{2} + 9) = 0 \\ 1) {x}^{2} = 0 \\ 2) {x}^{2} + 9 = 0$

Отсюда: х¹ = 0.