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4)[tex]0,04p^{2} -1,69q^{2}=\frac{1}{100}*(2p-13q)(2p+13q)" alt="
4)[tex]0,04p^{2} -1,69q^{2}=\frac{1}{100}*(2p-13q)(2p+13q)" align="absmiddle" class="latex-formula">
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8)0,81y^{10}-400z^{12}=(\frac{9}{10}y^{5}-20z^{6})(\frac{9}{10}y^{5}+20z^{6})
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