Помогите пожалста решить(a.b)

Решите задачу:

${27}^{ - 3} \times {9}^{7} = {( {3}^{3} })^{ - 3} \times {( {3}^{2} )}^{7} = \\ = {3}^{ - 9} \times {3}^{14} = {3}^{ - 9 + 14} = \\ = {3}^{5} = 243$
$\frac{ {22}^{6} \times {2}^{ - 8} }{ {44}^{ - 3} \times {11}^{9} } = \frac{ {(2 \times 11)}^{6} \times {2}^{ - 8} }{ {(4 \times 11)}^{ - 3} \times {11}^{9} } = \\ = \frac{ {2}^{6} \times {11}^{6} \times {2}^{ - 8} }{ {( {2}^{2} )}^{ - 3} \times {11}^{ - 3} \times {11}^{9} } = \\ = \frac{ {2}^{6 - 8} \times {11}^{6} }{ {2 }^{ - 6} \times {11}^{ - 3 + 9} } = \frac{ {2}^{ - 2} \times {11}^{6} }{ {2}^{ - 6} \times {11}^{6} } = \\ = { 2}^{ - 2 - ( - 6)} = {2}^{4} = 16$