Пожалуйста,помогите определить log5 15, log5 12, log5 30 если log5 2=a log5 3=b
Log ab=log a + ljg b log5 2 =a log5 3 =b log5 15 = log5 5*3 = log5 5 + log5 3 a+b log5 12 = log5 ²*3 = 2log5 2 + log5 3 2a+b log5 30 = log5 5*2*3 = log5 5 +log5 2 + log5 3 1+a+b
Log5 15 = log5 5*3 = log5 5 + log5 3 = 1+b log5 12 = log5 2^2*3 = 2log5 2 + log5 3 = 2a+b log5 30 = log5 5*2*3 = log5 5 +log5 2 + log5 3 = 1+a+b