x²-12x+32=0
D/4=36-32=2²
x1=6-2=4; x2=6+2=8 ОДЗ х≠4; х≠8
(7-2х)/(х-4)(х-8)≥1/4 I *4
(7-2х)*4/(х-4)(х-8) - 1 ≥ 0
[4(7-2х)-(х-4)(х-8)]/(x-4)(x-8)≥0
[28-8x-x²+12x-32]/(x-4)(x-8)≥0
[-x²+4x-4]/(x-4)(x-8)≥0
(x-2)²/(4-x)(x-8)≥0
----------[2]-------(4)-----(8)----->x
- - + -
x∈(4; 8).