CH3COOH + CH3CH2OH=CH3COOC2H5 + H2O
m(CH3COOH) = 7.2г
m( CH3CH2OH) = 6.9 г
m.практ(CH3COOC2H5) = 9г
n(CH3COOH) = m(CH3COOH) / Mr(CH3COOH) = 7.2 / 60 = 0.12 моль
n(CH3COOH) = n(CH3COOC2H5)
m(CH3COOC2H5) = n(CH3COOC2H5) * Mr(CH3COOC2H5) = 0.12 * 88 = 10,56 грамм.
w = m(практ) / m(теор) * 100% = 9/10.56 * 100 = 85%
Ответ: 85%