Y=x(квадрат) x-3y=-3
1)xy+x-3y-3=0 x-3+y(x-3)=0 y(x-3)=3-x y=(3-x):(x-3) (2) x^2 + ((3-x):(x-3))^2=10 (x^2(x-3)^2+(3-x)^2):(x-3)^2=0 ((x^2-1)(x-3)^2):(x-3)^2 =0 x^2-1=0 x^2=1 x=-1, x=1 y^2=10-1 y^2=9 y= -3, y=3 Ответ - (-1;3) (-1;-3) (1;3) (1;-3)