Решите уравнение (7/18 + 5/24z) : 3 2/3 = 1/3

$( \frac{7}{18} + \frac{5}{24} z) \div 3 \frac{2}{3} = \frac{1}{3}$
ноз (18, 24)=72
$( \frac{28}{72} + \frac{15}{72} z) \div \frac{11}{3} = \frac{1}{3}$

$\frac{43}{72} \div \frac{11}{3}z = \frac{1}{3}$

$\frac{43}{72} \times \frac{3}{11} z = \frac{1}{3}$

$\frac{43}{264} z = \frac{1}{3}$

$z = \frac{1}{3 } \div \frac{43}{264}$

$z = \frac{1}{3} \times \frac{264}{43}$

$z = \frac{88}{43}$

z=1 2/43