=4} \atop {2x^2-8x+7x-28=0}} \right." alt="\left \{ {{x>=4} \atop {2x^2-8x+7x-28=0}} \right." align="absmiddle" class="latex-formula">
Скобка объединения

=4} \atop {(x-(1+15)/2)(x-(1-15)/2)=0}} \right." alt="\left \{ {{x>=4} \atop {(x-(1+15)/2)(x-(1-15)/2)=0}} \right." align="absmiddle" class="latex-formula">
Скобка объединения

Решение 1ой скобки
x>=4
x=8
x=-7
Подходит x=8
Решение 2ой скобки
x<4</p>
x=8
x=-7
Подходит x=-7
Ответ: x={-7;8}