Решите Уравнения (3x+5)(3x-5)-(3x-1)^2=-4(9x+2)(1-4x)+(5-6x)^2=-32

Решите задачу:

$1) {9x}^{2} - 25 - ( {9x}^{2} - 6x + 1) = - 4 \\ {9x}^{2} - 25 - 9 {x}^{2} + 6x - 1 = - 4$
$6x - 26 = - 4 \\ 6x = - 4 + 26 \\ 6x = 22 \\ x = 22 \div 6 = 3 \frac{4}{6} = 3 \frac{2}{3}$
$2)9x - 36 {x}^{2} + 2 - 8x + \\ (36 {x}^{2} - 60x + 25) = - 32 \\ x - 36 {x}^{2}+ 2 + 36 {x}^{2} - 60x + 25$
$- 59x + 27 = - 32 \\ - 59x = - 32 - 27 = - 59 \\ x = - 59 \div ( - 59) \\ x = 1$