Помогите решить! 1. √726/11 2. √432/12 3. √98/7 4. √648/18 5. √675/15 6. √875/5 7. √216/6...

Решите задачу:

$\frac{ \sqrt{726} }{11} = \frac{11 \sqrt{6} }{11} = \sqrt{6 }$
$\frac{ \sqrt{432} }{12} = \sqrt{36} = 6$
$\frac{ \sqrt{98} }{7} = \frac{7 \sqrt{2} }{7} = \sqrt{2}$
$\frac{ \sqrt{648} }{18} = \frac{18 \sqrt{2} }{18} = \sqrt{2}$
$\frac{ \sqrt{675} }{15} = \frac{15 \sqrt{3} }{15} = \sqrt{3}$
$\frac{875}{5} = \frac{5 \sqrt{35} }{5} = \sqrt{35}$
$\frac{ \sqrt{216} }{6} = \frac{6 \sqrt{6} }{6 } = \sqrt{6}$
$\frac{ \sqrt{486} }{9} = \frac{9 \sqrt{6} }{9} = \sqrt{6}$
$\frac{ \sqrt{1280} }{16} = \sqrt{80} = 4 \sqrt{5}$