Решите пожайлста ........

Решите задачу:

$1)\frac{1}{3}\sqrt{54}=\sqrt{\frac{1}{9}*54 }=\sqrt{6}\\\\3=\sqrt{9}\\\\\sqrt{6}<\sqrt{9}\\\\\frac{1}{3}\sqrt{54}<3$

$2)4\sqrt{50}=4\sqrt{25*2}=4*5\sqrt{2}=20\sqrt{2} \\\\5\sqrt{32}=5\sqrt{16*2} =5*4\sqrt{2}=20\sqrt{2}\\\\20\sqrt{2}=20\sqrt{2}\\\\4\sqrt{50} =5\sqrt{32}$

$3)5\sqrt{27}=5\sqrt{9*3}=5*3\sqrt{3}=15\sqrt{3}\\\\3\sqrt{75}=3\sqrt{25*3}=3*5\sqrt{3}=15\sqrt{3}\\\\15\sqrt{3}=15\sqrt{3} \\\\5\sqrt{27}=3\sqrt{75}$