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Единственная пара чисел, которые удовлетворяют условию:
Я ошибку нашёл, сейчас исправлю
![\frac{\sqrt{-x}+\sqrt{xy}}{1+\sqrt{\sqrt{y^2}}} -\sqrt{-x}=\frac{\sqrt{-x}+\sqrt{xy}-\sqrt{-x}-\sqrt{-x}\cdot \sqrt[4]{y^2}}{1+\sqrt[4]{y^2}}=\frac{\sqrt{xy}-\sqrt{-x}\sqrt{y}}{1+\sqrt{y}}\\OD3:-x\geq 0;x\leq 0;y\geq 0; xy\geq 0](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B-x%7D%2B%5Csqrt%7Bxy%7D%7D%7B1%2B%5Csqrt%7B%5Csqrt%7By%5E2%7D%7D%7D%20-%5Csqrt%7B-x%7D%3D%5Cfrac%7B%5Csqrt%7B-x%7D%2B%5Csqrt%7Bxy%7D-%5Csqrt%7B-x%7D-%5Csqrt%7B-x%7D%5Ccdot%20%5Csqrt%5B4%5D%7By%5E2%7D%7D%7B1%2B%5Csqrt%5B4%5D%7By%5E2%7D%7D%3D%5Cfrac%7B%5Csqrt%7Bxy%7D-%5Csqrt%7B-x%7D%5Csqrt%7By%7D%7D%7B1%2B%5Csqrt%7By%7D%7D%5C%5COD3%3A-x%5Cgeq%200%3Bx%5Cleq%200%3By%5Cgeq%200%3B%20xy%5Cgeq%200 "\frac{\sqrt{-x}+\sqrt{xy}}{1+\sqrt{\sqrt{y^2}}} -\sqrt{-x}=\frac{\sqrt{-x}+\sqrt{xy}-\sqrt{-x}-\sqrt{-x}\cdot \sqrt[4]{y^2}}{1+\sqrt[4]{y^2}}=\frac{\sqrt{xy}-\sqrt{-x}\sqrt{y}}{1+\sqrt{y}}\\OD3:-x\geq 0;x\leq 0;y\geq 0; xy\geq 0")
![\frac{\sqrt[4]{x^2y^2}-\sqrt[4]{(-x)^2y^2}}{1+\sqrt{y}} =\frac{0}{1+\sqrt{y}}=0](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7Bx%5E2y%5E2%7D-%5Csqrt%5B4%5D%7B%28-x%29%5E2y%5E2%7D%7D%7B1%2B%5Csqrt%7By%7D%7D%20%3D%5Cfrac%7B0%7D%7B1%2B%5Csqrt%7By%7D%7D%3D0 "\frac{\sqrt[4]{x^2y^2}-\sqrt[4]{(-x)^2y^2}}{1+\sqrt{y}} =\frac{0}{1+\sqrt{y}}=0")