\sqrt{6} \ \ \Rightarrow \ \ \dfrac{1}{2}\cdot\sqrt{40} >\dfrac{1}{3}\cdot \sqrt{54}" alt="\dfrac{1}{2}\cdot\sqrt{40}=\sqrt{40\cdot \dfrac{1}{4}}=\sqrt{10} \\ \dfrac{1}{3}\cdot \sqrt{54} =\sqrt{\dfrac{1}{9}\cdot54}=\sqrt{6} \\ \\ \sqrt{10} > \sqrt{6} \ \ \Rightarrow \ \ \dfrac{1}{2}\cdot\sqrt{40} >\dfrac{1}{3}\cdot \sqrt{54}" align="absmiddle" class="latex-formula">