Решите пожалуйста !!!!

Решите задачу:

$ab + yb - ac - yc = a(b - c) + y(b - c) = (a + y)(b - c)$
$3x + 3y - bx - by = 3(x + y) - b(x + y) = (3 - b)(x + y)$
$4n - nc - 4 + c = 4(n - 1) - c(n - 1) = (4 - c)(n - 1)$
${x}^{7} + {x}^{3} - 4 {x}^{4} - 4 = {x}^{3} ( {x}^{4} + 1) - 4( {x}^{4} - 1) = ( {x}^{3} - 4)( {x}^{4} - 1)$
$6mn - 3m + 2n - 1 = 3m(2n - 1) + (2n - 1) = (3m + 1)(2n - 1)$
$4 {a}^{4} - 5 {a}^{3} y - 8a + 10y = 4a( {a}^{3} - 2) - 5y( {a}^{3} - 2) = (4a - 5y)( {a}^{3} - 2)$
$24 {x}^{2} y + 36x {y}^{2} = 12xy(2x + 3y)$
$- 4 {x}^{8} + 18 {x}^{15} = 2 {x}^{8} (9 {x}^{7} - 2)$
$3 {x}^{4} - 6 {x}^{3} + 9 {x}^{5} = 3 {x}^{3} (x - 2 + 3 {x}^{2} )$
$8a {b}^{3} - 12 {a}^{2} b - 24 {a}^{2} {b}^{2} = 4ab(2 {b}^{2} - 3a - 6ab)$
$18 {y}^{5} - 12x {y}^{2} + 9 {y}^{3} = 3 {y}^{2} (6 {y}^{3} - 4x + 3y)$
$- 14a {b}^{3} {c}^{2} - 21 {a}^{2}b {c}^{2} - 28 {a}^{3} {b}^{2} c = - 7abc(2 {b}^{2} c + 3ac + 4 {a}^{2} b)$