|3x-1| < 5-x
3x-1 ≥ 0 x ≥1/3 3x-1 < 0 x <1/3</p>
3x-1< 5-x 1-3х < 5-x
4x< 6 2x> -4
x<3/2 x> -2
x∈ [1/3 ; 3/2) x (-2; 1/3)
х∈ (-2 ; 3/2)
|5x-7|≥ |x-1|
(5x-7)² ≥ (x-1)²
25x-70x+49 ≥ x²-2x+1
24x²- 68x+48 ≥0
6x²-17x+12≥ 0
D= 289- 288=1
x₁=(17+1)/12= 18/12 =3/2
x₂=(17-1)/12= 16/12= 4/3
+ - +
________3/2 ________4/3______
x∈(-∞ ; 3/2] ∪[ 4/3 ;+∞)