Log2(x+1)-log2(8-x)=2

Question

Log2(x+1)-log2(8-x)=2

Answer 1

Log2x + log2 - log16 + log2x - 2 = 0
log4x - log14 - 2 = 0
log2 (2x-log7) = 0
(log2-1)•(x-log3,5)=0
log2-1=0 или x-log3,5=0
log=0,5 log= -2,5