Помогите решить пожалуйста

Question 1

Question 2

$1)(\frac{2}{3})^{x}*(\frac{27}{8})^{-7}\geq\frac{81}{16}\\\\(\frac{3}{2})^{-x}*(\frac{3}{2})^{-21}\geq(\frac{3}{2})^{4}\\\\(\frac{3}{2})^{-x-21}\geq(\frac{3}{2})^{4}\\\\-x-21\geq4\\\\-x\geq 25\\\\x\leq-25$

Ответ : x ∈ (- ∞ ; - 25]

0\\\\243m^{2}-9m-2\leq0\\\\D=(-9)^{2}-4*243*(-2)=81+1944=2025=45^{2}\\\\m_{1}=\frac{9+45}{486}=\frac{54}{486}=\frac{1}{9}=3^{-2}\\\\m_{2}=\frac{9-45}{486}=-\frac{36}{486} <0\\\\3^{x}=3^{-2}\\\\x=-2" alt="2)3^{2x+5}\leq 3^{x+2}+2\\\\3^{2x} *3^{5}-3^{x}*3^{2} -2\leq0\\\\243*3^{2x}-9*3^{x}-2\leq0\\\\3^{x} =m,m>0\\\\243m^{2}-9m-2\leq0\\\\D=(-9)^{2}-4*243*(-2)=81+1944=2025=45^{2}\\\\m_{1}=\frac{9+45}{486}=\frac{54}{486}=\frac{1}{9}=3^{-2}\\\\m_{2}=\frac{9-45}{486}=-\frac{36}{486} <0\\\\3^{x}=3^{-2}\\\\x=-2" align="absmiddle" class="latex-formula">

Question 3

не поможете мне

Question 4

с алгеброй?

Universalka_zn · Answer 1 · 2020-05-24T12:40:32+0000

$1)(\frac{2}{3})^{x}*(\frac{27}{8})^{-7}\geq\frac{81}{16}\\\\(\frac{3}{2})^{-x}*(\frac{3}{2})^{-21}\geq(\frac{3}{2})^{4}\\\\(\frac{3}{2})^{-x-21}\geq(\frac{3}{2})^{4}\\\\-x-21\geq4\\\\-x\geq 25\\\\x\leq-25$

Ответ : x ∈ (- ∞ ; - 25]

0\\\\243m^{2}-9m-2\leq0\\\\D=(-9)^{2}-4*243*(-2)=81+1944=2025=45^{2}\\\\m_{1}=\frac{9+45}{486}=\frac{54}{486}=\frac{1}{9}=3^{-2}\\\\m_{2}=\frac{9-45}{486}=-\frac{36}{486} <0\\\\3^{x}=3^{-2}\\\\x=-2" alt="2)3^{2x+5}\leq 3^{x+2}+2\\\\3^{2x} *3^{5}-3^{x}*3^{2} -2\leq0\\\\243*3^{2x}-9*3^{x}-2\leq0\\\\3^{x} =m,m>0\\\\243m^{2}-9m-2\leq0\\\\D=(-9)^{2}-4*243*(-2)=81+1944=2025=45^{2}\\\\m_{1}=\frac{9+45}{486}=\frac{54}{486}=\frac{1}{9}=3^{-2}\\\\m_{2}=\frac{9-45}{486}=-\frac{36}{486} <0\\\\3^{x}=3^{-2}\\\\x=-2" align="absmiddle" class="latex-formula">