Решите систему 1/х+1/у=5/6 2у-х=1
1/x+1/y=(x+y)/(x*y)=5/6
x=2y-1⇒⇒
(3y-1)/(2*y^2-y)=5/6
18y-6=10y²-5y
10y²-23y+6=0 y1=3/10, y2=2
x1=-2/5 x2=3