A = ∛(x + 24) -> 3
B = ∛(12x - 9) -> 3
C = √(x + 1) -> 2
\frac{4}{27} * \frac{(x + 24) - (12x - 9)}{(x+1) - 4} = \frac{4}{27}*\frac{-11x + 33}{x - 3} = \frac{4}{27}*(-11) = - \frac{44}{27}" alt="\frac{A - B}{C - 2} = \frac{(A - B)(A^2 + AB + B^2)}{A^2 + AB + B^2} * \frac{C + 2}{(C - 2)(C + 2)} = \frac{A^3 - B^3}{C^2 - 4}*\frac{C + 2}{A^2 + AB + B^2} -> \frac{4}{27} * \frac{(x + 24) - (12x - 9)}{(x+1) - 4} = \frac{4}{27}*\frac{-11x + 33}{x - 3} = \frac{4}{27}*(-11) = - \frac{44}{27}" align="absmiddle" class="latex-formula">
Lim = -44/27