Помогите пожалуйста решить 2 уравнения

$\displaystyle \tt a). \ \ 2\frac{1}{3}:\bigg(x-1\frac{1}{6}\bigg)=1\frac{5}{9}\\\\\\{} \ \ \ \ \ \ x-1\frac{1}{6}=2\frac{1}{3}:1\frac{5}{9}\\\\{} \ \ \ \ \ \ x=\frac{7}{3}\cdot\frac{9}{14}+1\frac{1}{6}\\\\{} \ \ \ \ \ \ x=\frac{9}{6}+\frac{7}{6}\\\\{} \ \ \ \ \ \ x=2\frac{2}{3}$

Ответ: {2 2/3}

$\displaystyle \tt b). \ \ 27:\bigg(31\frac{3}{7}-2\frac{11}{14}x\bigg)=1\frac{1}{8}\\\\\\{} \ \ \ \ \ \ 31\frac{3}{7}-2\frac{11}{14}x=27:\frac{9}{8}\\\\{} \ \ \ \ \ \ 31\frac{3}{7}-2\frac{11}{14}x=24\\\\{} \ \ \ \ \ \ 2\frac{11}{14}x=31\frac{3}{7}-24\\\\{} \ \ \ \ \ \ x=7\frac{3}{7}:2\frac{11}{14}\\\\{} \ \ \ \ \ \ x=\frac{52}{7}\cdot\frac{14}{39}\\\\{} \ \ \ \ \ \ x=2\frac{2}{3}$

Ответ: {2 2/3}