0}} \right. \\\\1)2x^{2}-7x-4=0\\\\D=(-7)^{2} -4*2*(-4)=49+32=81=9^{2}\\\\x_{1} =\frac{7+9}{4}=4\\\\x_{2}=\frac{7-9}{4} =-0,5\\\\2x^{2}-7x-4=2(x-4)(x+0,5)\\\\2(x-4)(x+0,5)\leq0\\\\(x-4)(x+0,5)\leq 0" alt="\left \{ {{2x^{2}-7x-4\leq0} \atop {2x-3>0}} \right. \\\\1)2x^{2}-7x-4=0\\\\D=(-7)^{2} -4*2*(-4)=49+32=81=9^{2}\\\\x_{1} =\frac{7+9}{4}=4\\\\x_{2}=\frac{7-9}{4} =-0,5\\\\2x^{2}-7x-4=2(x-4)(x+0,5)\\\\2(x-4)(x+0,5)\leq0\\\\(x-4)(x+0,5)\leq 0" align="absmiddle" class="latex-formula">
+ - +
_________[- 0,5]_________[4]_________
x ∈ [- 0,5 ; 4]
2) 2x - 3 > 0
2x > 3
x > 1,5
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___________[- 0,5]________(1,5)_________[4]________
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Ответ : (1,5 ; 4]