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У. $9\frac{3}{20} - 2\frac{3}{25} - 4 = 9\frac{15}{100} - 2\frac{12}{100} - 4 = 7\frac{3}{100} - 4 = 3\frac{3}{100}$

Л. $13-5\frac{7}{12}-1\frac{4}{15} = 13 - (5\frac{7}{12}+1\frac{4}{15}) = 13 - (5\frac{35}{60} + 1\frac{16}{20}) = 13 - 6\frac{51}{60} = 13 - 6\frac{17}{20} = 7-\frac{17}{20} = 6\frac{3}{20}$

Г. $5\frac{11}{42}-2\frac{3}{14}-1\frac{1}{21}=5\frac{11}{42}-2\frac{9}{42}-1\frac{2}{42}=2\frac{11-9-2}{42}=2$

Б. $11 - 6\frac{13}{21}-\frac{3}{14} = 11 - (6\frac{13}{21} + \frac{3}{14}) = 11 - (6\frac{26}{42} + \frac{9}{42}) = 11-6\frac{35}{42}=11-6\frac{5*7}{6*7}=11-6\frac{5}{6} = 5-\frac{5}{6} = 4\frac{1}{6}$