Нужно решить уравнение. срочно.
Замена log(1/3) x = y, тогда log(x) (1/3) = 1/y y + 2 = 3/y y^2 + 2y - 3 = 0 (y + 3)(y - 1) = 0 y1 = log(1/3) x1 = -3, x1 = (1/3)^(-3) = 3^3 = 27 y2 = log(1/3) x2 = 1, x2 = 1/3