Помогите плиииз /544

Решите задачу:

$3 \ \frac{1}{8} + 5 \frac{3}{8} + 7 \frac{5}{12} + \frac{1}{12 } =8 \frac{1}{2} + 7 \frac{1}{2} = 16$
$10 \frac{2}{5} + 3\frac{3}{5} + 15 \frac{5}{6} + 4 \frac{1}{6} = 14 + 20 = 34$
$9 \frac{7}{8} + 1\frac{1}{8} + 5 \frac{2}{7} + 4 \frac{5}{7} = 11 + 10 = 21$
$15 \frac{7}{18} + \frac{5}{18} + 11 \frac{8}{9} + \frac{4}{9} = 15 \frac{2}{3} + 12 \frac{1}{3} = 28$