Помогите решить, пожалуйста с объяснением

x + 3 \\ 5x + 11 > {(x + 3)}^{2} \\ 5x + 11 > {x}^{2} + 6x + {3}^{2} \\ 5x + 11 > {x}^{2} + 6x + 9 \\ 11 - 9 > {x}^{2} + 6x - 5x \\ 2 > {x}^{2} + x \\ {x}^{2} + x < 2" alt=" \sqrt{5x + 11} > x + 3 \\ 5x + 11 > {(x + 3)}^{2} \\ 5x + 11 > {x}^{2} + 6x + {3}^{2} \\ 5x + 11 > {x}^{2} + 6x + 9 \\ 11 - 9 > {x}^{2} + 6x - 5x \\ 2 > {x}^{2} + x \\ {x}^{2} + x < 2" align="absmiddle" class="latex-formula">
$\sqrt{3 - x} < \sqrt{3x - 5}$
$3 - x < 3x - 5 \\ - x - 3x < - 5 - 3 \\ - 4x < - 8 \\ x < 2$