Реши уравнение 1) 2х+32=170 2) 463-4у=219 3) (246+а)-42=643

Question

Реши уравнение 1) 2х+32=170 2) 463-4у=219 3) (246+а)-42=643

Comments

На листочке

Answer 1

1)2х=170-32

2х=138

х=138:2

х=69

2)-4у=219-463

-4у=-244

-4у:(-4)=-244:(-4)

у=-244:(-4)

у=244:4

у=61

3)246+а-42=643

204+а=643

204+а-204=643-204

а=643-204

а=439

Comments

Спасибо тебе помог

Answer 2

2x = 170 - 32 < = > 2x = 138 < = > x = 69" alt="2x + 32 = 170 < = > 2x = 170 - 32 < = > 2x = 138 < = > x = 69" align="absmiddle" class="latex-formula">
- 4y = 219 - 463 < = > - 4y = - 244 < = > y = 61" alt="463 - 4y = 219 < = > - 4y = 219 - 463 < = > - 4y = - 244 < = > y = 61" align="absmiddle" class="latex-formula">
246 + a - 42 = 643 < = > a = 643 - 204 < = > a = 439" alt="(246 + a) - 42 = 643 < = > 246 + a - 42 = 643 < = > a = 643 - 204 < = > a = 439" align="absmiddle" class="latex-formula">

Comments

А можно на листочке