Решите уравнение : а) -8 (11-2а) + 40 = 3 (5а-4) б) 7 (-3 ( m-2)-m)-12=4 (5-3m)-4
-8(11-2a)+40=3(5a-4) -88-16a+40=15a-12 -16a+15a=-12+48 -1a=36 a=36÷(-1) a=-36 7(-3(m-2)-m)-12=4(5-3m)-4 7(-3m+6-m)-12=20-12m-4 7(-4m+6)-12=16-12m -28m+42-12=16-12m -28m+12m=16-30 -16m=-14 m=14/16 m=7/8