0\\\\x_1=-12\; ,\; x_2=4\; ,\; x_3=20\\\\znaki:\; \; ---(-12)+++(4)---(20)+++\\\\x\in (-12,4)\cup (20,+\infty )" alt="1)\; \; \frac{x^2-3x-18}{x^2-10x+25}\leq 0\; \; ,\; \; \frac{(x-6)(x+3)}{(x-5)^2}\leq 0\\\\x_1=-3\; ,\; x_2=6\; ,\; x_3\ne 5\\\\znaki:\; \; ---[-3\, ]+++(5)---[\, 6\, ]+++\\\\x\in (-\infty ,-3\, ]\cup (5,6\, ]\\\\2)\; \; (x+12)(x-4)(x-29)>0\\\\x_1=-12\; ,\; x_2=4\; ,\; x_3=20\\\\znaki:\; \; ---(-12)+++(4)---(20)+++\\\\x\in (-12,4)\cup (20,+\infty )" align="absmiddle" class="latex-formula">