2\7)^ (3(X-1\3) < ( 2\7)^2^X^2
3(X - 1\3) < 2*X^2
3X - 1 < 2X^2
- 2X^2 + 3X - 1 < 0
D = 9 - 4*(-2)*(-1) = 9 - 8 = 1 ; V D = 1
X1 = ( - 3 + 1 ) : ( - 4 ) = + 0.5
X2 = ( -4) : ( - 4) = + 1
X1 < 0.5 X2 < 1
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0.5 1
Ответ: ( - бесконечность ; 0.5 )