2x^2\\\\2x^2-3x+1<0\\\\ D=9-8=1\\\\ x_1=\frac{3-1}{4}=0.5\\\\ x_2=\frac{3+1}{4}=1" alt="\displaystyle \tt \left(\frac{2}{7}\right)^{3(x-\frac{1}{3})} <\left(\frac{4}{49}\right)^{x^2}\\\\\\ \left(\frac{2}{7}\right)^{3x-1} <\left(\frac{2}{7}\right)^{2x^2}\\\\\\ 3x-1>2x^2\\\\2x^2-3x+1<0\\\\ D=9-8=1\\\\ x_1=\frac{3-1}{4}=0.5\\\\ x_2=\frac{3+1}{4}=1" align="absmiddle" class="latex-formula">
+ - +
----------(0.5)--------------(1)------------->
