Решите систему уравнений методом алгебраического сложения. x^2-3y^2=22 x^2+3y^2=28

Решите задачу:

$\left \{ {{}x^{2}-3 y^{2}=22 \atop x^{2}+3 y^{2}=28 } \right. \left \{ {{}2x^{2}=50 \atop x^{2}+3 y^{2}=28 } \right. \\\left \{ {{}x^{2}=25 \atop x^{2}+3 y^{2}=28 } \right. \\\left \{ {{}x}=+-5 \atop x^{2}+3 y^{2}=28 } \right. \\\left \{ {{}x}=+-5 \atop 5^{2}+3 y^{2}=28 } \right. \\\\\left \{ {{}x}=+-5 \atop 3 y^{2}=3 } \right. \\\\\left \{ {{}x}=+-5 \atop y=+-1 } \right. \\$