\frac{17}{20}" alt="\frac{17}{20};\frac{1}{40};\frac{3}{60}\\ \\\frac{17*6}{20*6};\frac{1*3}{40*3};\frac{3*2}{60*2}\\ \\\frac{102}{120};\frac{3}{120};\frac{6}{120}\\ \\\frac{102}{120} =>\frac{17}{20}" align="absmiddle" class="latex-formula">
Ответ: первая наибольшая