(7p⁴/10q³)/(5q/14p²)/(3p/4q⁴)

Question

(7p⁴/10q³)/(5q/14p²)/(3p/4q⁴)

Answer 1

3p-7/9 - 4p+1/6=3p-4p +1/6 - 7/9= -p+ (3-7*2) /3*3*2 = -p - 11/18
(3p-7)/9 - (4p+1)/6=2(3p-7)-3(4p+1)/3*3*2=(6p-14-14p-3)/18=(-8p-17)/18=-(8p+17)/18