2) дано
m(Zn) = 65 g
m(ppa HCL) = 300 g
W(HCL) = 10%
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V(H2)-?
m(HCL) = 300*10% / 100% = 30 g
M(Zn) = 65 g/mol
n(Zn) = m/M = 65 /65 = 1 mol
M(HCL) = 36.5 g/mol
n(HCL) = m/M = 30 / 36.5 = 0.82 mol
n(Zn) > n(HCL)
Zn+2HCL-->ZnCL2+H2
2n(HCL) = n(H2)
n(H2) = 0.82 / 2 = 0.41 mol
v(H2) =n(H2) * Vm = 0.41 * 22.4 = 9.184 L
ответ 9.184 л
3)
дано
m(ppa H3PO4) = 200 g
W(H3PO4) = 10%
m(ppa LiNO3) = 300 g
w(LiNO3) = 15%
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m(Li3PO4)-?
m(H3PO4) = 200*10% / 100% = 20 g
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 20 /98 = 0.2 mol
m(LiNO3) = 300 * 15% / 100% = 45 g
M(LiNO3) = 69 g/mol
n(LiNO3) =m/M = 45 / 69 = 0.65 mol
n(H3PO4) < n(LiNO3)
H3PO4+3LiNO3-->Li3PO4+3HNO3
n(H3PO4) =n( Li3PO4) = 0.2 mol
M(Li3PO4) = 116 g/mol
m(Li3PO4) = n*M = 0.2 * 116 = 23.2 g
ответ 23.2 г