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3 \\ x > 0 \\ x < 3 \\ x < 0 \\ x = ( - \infty; 0)U(3; + \infty )" alt=" \frac{6}{x} + \frac{6}{x} + 1 < 5 \\ 2 \times \frac{6}{x} + 1 < 5 \\ \frac{12 - 4x}{x} < 0 \\ x > 3 \\ x > 0 \\ x < 3 \\ x < 0 \\ x = ( - \infty; 0)U(3; + \infty )" align="absmiddle" class="latex-formula">