Решите алгебру, пожалуйста

Решите задачу:

$10(1 - 2x) = 5(2x - 3) - 3(11x - 5) \\ 10 - 20x = 10x - 15 - 33x + 15 \\ 33x - 20x - 10x = - 10 \\ 3x = - 10 \\ x = - \frac{10}{3}$
$(1 - 5.1x) - (1.7x + 5.4) = 1 \\ 1 - 5.1x - 1.7x - 5.4 = 1 \\ 5.1x + 1.7x = - 5.4 \\ 6.8x = - 5.4 \\ x = - 5.4 \div 6.8 \\ x = - 5 \frac{2}{5} \div 6 \frac{4}{5} \\ x = - \frac{27}{5} \div \frac{34}{5} \\ x = - \frac{27 \times 5}{5 \times 34} \\ x = - \frac{27}{34}$
${(2x - 3)}^{2} - {(2x + 3)}^{2} = 12 \\ (2x - 3 + (2x + 3))(2x - 3 - (2x + 3)) = 12 \\ (2x - 3 + 2x + 3)(2x - 3 - 2x - 3) = 12 \\ 4x \times ( - 6) = 12 \\ - 24x = 12 \\ x = - \frac{12}{24} \\ x = - \frac{1}{2}$